find the dimensions of a rectangle with perimeter 28mts and area is 40sq mts
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Step-by-step explanation:
given
perimeter=28m
so,
2(l+b)=28
l+b=14--------(1)
area=40m^2
thus
l*b=40
l=40/b
now putting the value of l in equation 1
40/b+b=14
40+b^2/b=14
hence:-
b-4=0
b=4
b-10=0
b=10
therefore,
the dimensions of rectangle
length=10m
breadth=4m
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