Question

Find the dimensions of a rectangle with perimeter
72 units and whose length is five times its breadth.
Also, find its area.​

Answer 1

Answer:

Length of the rectangle=30 units

Breadth of the rectangle=6 units

Area of the rectangle=180 sq.units

Step-by-step explanation:

Given:-

A rectangle with perimeter 72 units and whose length is five times its breadth.

To find:-

Find the dimensions of a rectangleAlso, find its area.

Solution:-

Let the breadth of a rectangle be b units

And the length of the rectangle = Five times to its breadth

=>5b units

the perimeter of the rectangle=2(l+b) units

According to the given problem, the perimeter of the given rectangle=72 units

=>2(l+b)=72

=>2(5b+b)=72

=>2(6b)=72

=>12b=72

=>b=72/12

=>b=6 units

and 5b=5(6)=30 units

Length of the rectangle=30 units

Breadth of the rectangle=6units

Area of the rectangle=l×b sq.units

=>30×6

=>180sq.units.

Answer:-

Length of the rectangle=30 units

Breadth of the rectangle=6 units

Area of the rectangle=180 sq.units

Answer 2

Let Breadth of Rectangle be x units

• So Length of Rectangle will be 5x units

Perimeter of Rectangle = 2 × (Length + Breadth)

⇒ 72 units = 2 × (5x + x)

⇒ 72 units = 2 × 6x

⇒ 72 units = 12x

⇒ x = 72/12 units

⇒ x = 6 units

Then We get :

• Length = 5x units = 5 × 6 units = 30 units
• Breadth = x units = 6 units

Area of Rectangle = Length × Breadth

⇒ Area of Rectangle = 30 units × 6 units

⇒ Area of Rectangle = 180 sq. units