Question

find the dimensions of a rectangular Park whose perimeter is 60 M and area 200 m square

Answer 1

P=2(L+B)

20=2(L+B)

L+B=10 ---Equ.1

A=L×B

200=L×B

L=200/B Put in Equ.1

(200/B)+B=10

200+B^2=10B

B^2-10B+200=0

(B^2-20B)(10B+200)=0

B(B-20)+10(B-20)=0

B+10=0 B-20=0

B=-10 B=20

(Not possible)

Therefore B=20m

and L =200/B=200/20=10m