find the dimensions of a rectangular Park whose perimeter is 60 M and area 200 m square
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P=2(L+B)
20=2(L+B)
L+B=10 ---Equ.1
A=L×B
200=L×B
L=200/B Put in Equ.1
(200/B)+B=10
200+B^2=10B
B^2-10B+200=0
(B^2-20B)(10B+200)=0
B(B-20)+10(B-20)=0
B+10=0 B-20=0
B=-10 B=20
(Not possible)
Therefore B=20m
and L =200/B=200/20=10m
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