Physics, asked by patelamanaditya, 6 hours ago

Find the dimensions of (a) the specific heat capacity c, (b) the coefficient of linear expansion a and (c) the gas constant R. Some of the equations involving these quantities are Q = mc(T₂-T₁), l_{t} = l_{0}[1 + alpha(T_{2} - T_{1})] and PV = nRT.​

Answers

Answered by kkbanu02
0

Answer:

Here is ur answer

Explanation:

Heat energy (9). At = mc At "change in temperature.

where, m = mass of body C= specific heat capacity

C=Φ/m×delta*t

Unit of heat = Joule =kg m 5^-²

Dimension of d = Q = ML²T-².

C = [M * L ^ 2 * T ^ - 2]/([M][theta]) C = [L ^ 2 * T ^ - 2 * theta ^ - 1]

Lt=Lo [1+alphaCT₂-T1]

alpha = (l_{t} - l_{o})/l_{0}(t2-t1)

R=pv/nt

R = [ML^-1T² ] [L³] = [ML²T^-² mol'-1 K^-¹] [mol] [K+¹]

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