Question

Find the dimensions of a x b in the relation : P = , where P is power, x is at

b−x

2

distance and t is time.​

Answer 1

Explanation:

The given relation is P=b−x2at

As x2 is subtracted from b, therefore, the

dimensions of are of x2,i.e.,b=[L2]

we can rewrite relation (i) as P=L2at

or a=L2Pt=L2[ML2T−3][T]=[M−1L0T2]

****Good luck****