Question

Find the dimensions of (a xb) in the equation :
b-x
E
; where E is energy, x is distance and t is
time​

Answer 1

Answer:

E = ( b -x²) /at

= ( b/at - x²/at)

where E = energy

t = time

x = displacement.

so,

dimension of E = dimension of { b/at }

b/at = E

b/a = Et

dimension of {a/b} = 1/Et = 1/[ ML²T-²][ T]

= [ M-¹ L-²T]

Explanation:

Answer 2

$a= [M^-1 T^-1] , b=[L^2]$

Explanation:

$E=b-x^2/at$

using principle of homogeneity

$b= x^2 = [L^2]$

$a= b-x^2/Et$

$a= [L^2]/[ML^2][T]$

$a= [MT^-1]$