Question

find the dimensions of D and E in x=dt3/E+t​

Answer 1

Answer:

Explanation:

Given that,

x=a+bt+ct  

2

+dt  

3

 

x is the displacement.

Now, by principle of homogeneity

a=bt=ct  

2

=dt  

3

=x

Now, a=L

 [bt]=[L]

b=[LT  

−1

]

c=[LT  

−2

]

d=[LT  

−3

]

Hence, the dimension of a, b, c and d is [L],[LT  

−1

],[LT  

−2

]and[LT  

−3

]

Answer 2

Explanation:

find the dimensions of D and E in x=dt3/E+t