Question

find the dimensions of rectangale with a perimiter of 54meters , if its
leanth is 3 meters more than twice its width. ​

Answer 1

Answer:

answer is 19m

Step-by-step explanation:

width of rectangle = w m

then lenght = 3+2w m

given that ,

perimeter = 54 m

so,

54 = 2(w+3+2w)

27 = 3w+3

W = 8 m & lenght = 3+2×8 = 19 m

Answer 2

Answer:

this is your answer

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