Physics, asked by palakjain9403, 9 months ago

find the dimensions of the constants a , b, c and d in the relation v = a +bt + c/d+t where v is velocity and t is time.

Answers

Answered by oyeah3258
15

Answer:

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Answered by archanajhaasl
7

Answer:

The dimensions of the constants a, b, c, and d are [M⁰LT⁻¹], [M⁰LT⁻²],[T], and [M⁰LT⁰].

Explanation:

The given equation is of the form,

v=a+bt+\frac{c}{d+t}     (1)

Now let's find the dimensions one by one.

For "a"

[a]=[v]     (2)

The dimensions of velocity are =[M⁰LT⁻¹]

So,

[a]=[M^0LT^-^1]      (3)

For "b"

[bt]=[v]

So,

[bT]=[M^0LT^-^1]

[b]=[M^0LT^-^2]     (4)

For "d"

As dimensionally equal values are added together so the dimensions of d will be the same as that of time i.e.

[d]=[T]    (5)

For 'c'

\frac{[c]}{[d+t]}=[v]

So,

\frac{[c]}{[T]}=[M^0LT^-^1]

[C]=[M^0LT^-^1][T]

[C]=[M^0LT^0]   (6)

Hence, the dimensions of the constants a, b, c, and d are [M⁰LT⁻¹], [M⁰LT⁻²],[T], and [M⁰LT⁰].

#SPJ2

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