Physics, asked by sonalisatyam11, 12 days ago

find the direction cosines for the vector a = 4 i+6j -5k.​

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Answered by Anonymous
4

\huge\boxed{\fcolorbox{red}{ink}{Answer}}

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â=4 î+6j-5k

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The direction ratio of the vector are 4,6,-5

The direction cosines are

 \frac{4}{ \sqrt{ {4}^{2}  +  {6}^{2}  +  {5}^{2} } },\frac{6}{ \sqrt{77} } , \frac{5}{ \sqrt{77} }

➭ \frac{ + }{  } \frac{4}{8.77}   \:  \frac{ + }{}  \frac{6}{8.77}

Answered by Anonymous
0

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 \rm \underline \red{refer \: the \: attachment}

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