Find the direction cosines of line which makes a equalangles with the coordinate axes
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If A , B , C are the angle that a line makes with the co-ordinate axes then
We Know from the formula of direction cosine is
Cos²A + cos²B + cos²C = 1 …,,,,,,,,,,,,,,(1 )
Since the line make equal angle with the
co-ordinate axes then
A= B=C= X ( let)……………………….(2)
Hence from equation (1) & (2) we get
cos²x + cos²x + cos²x = 1
3cos²x = 1
Cos²x= 1/3
Cosx = 1/√3
Now cosA = cosB= cosC = ±1/√3
Hence the required direction cosine are
±1/√3 , ±1/√3 , ±1/√3 Ans
HOPE ITS HELPS....
We Know from the formula of direction cosine is
Cos²A + cos²B + cos²C = 1 …,,,,,,,,,,,,,,(1 )
Since the line make equal angle with the
co-ordinate axes then
A= B=C= X ( let)……………………….(2)
Hence from equation (1) & (2) we get
cos²x + cos²x + cos²x = 1
3cos²x = 1
Cos²x= 1/3
Cosx = 1/√3
Now cosA = cosB= cosC = ±1/√3
Hence the required direction cosine are
±1/√3 , ±1/√3 , ±1/√3 Ans
HOPE ITS HELPS....
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