Question

Find the direction cosines of the line which bisects the angle between positive direction of Y
and Z axes

Answer 1

$(0,\frac {1}{\sqrt 2},\frac {1}{\sqrt 2})$ are Directional Cosines

Step-by-step explanation:

• The Cosines of angle in between vector and 3 coordinate axes of vector, is what called as its directional cosines.

• Equivalently, they are the contributions of each component of the basis to a unit vector in that direction

• Vector parallel to bisector of the angle between positive YY & ZZ direction  

= $\widehat{j} + \widehat{k}$

universal = $\frac {\widehat{i}}{\sqrt 2} + \frac {\widehat{k}}{\sqrt 2}$

Directional Cosines = $(0,\frac {1}{\sqrt 2},\frac {1}{\sqrt 2})$