Math, asked by nakkafrank, 6 hours ago

find the direction cosines of the sides of the triangle whose vertices are ( 3,5,-4),(-1,1,2)and( -5,-5,-2)​

Answers

Answered by komal584
2

Answer:

Answer

Let, A(3,5,−4),B(−1,1,2) and C(−5,−5,−2)

(i) Direction ratios of the line joining A and B are

(−1−3),(1−5),(2−(−4))=(−4,−4,6)

∴AB=

(−4)

2

+(−4)

2

+6

2

=

16+16+36

=

68

=2

17

The direction cosines are

2

17

−4

,

2

17

−4

,

2

17

6

=

17

−2

,

17

−2

,

17

3

(ii) Direction ratios of the line joining B and C are

(−5−(−1)),(−5−1),(−2−2)=(−4,−6,−4)

∴BC=

(−4)

2

+(−6)

2

+(−4)

2

=

16+36+16

=

68

=2

17

The direction cosines are

2

17

−4

,

2

17

−6

,

2

17

−4

=

17

−2

,

17

−3

,

17

−2

(iii) Direction ratios of the line joining C and A are

(3−(−5)),(5−(−5)),(−4−(−2))=(8,10,−2)

∴CA=

(8)

2

+(10)

2

+(−2)

2

=

64+100+4

=

168

=2

42

The direction cosines are

2

42

8

,

2

42

10

,

2

42

−2

=

42

4

,

42

5

,

42

−1

Two of the sides are equal, so the triangle is an isosceles triangle.

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