Find the direction cosines of two lines which are connected by the Relations l+m+n=0,l²+m²+n²=0
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Step-by-step explanation:
- Eliminating n from both the equations, we have
- P+ m² (+ m)²=0 P²+m²-P-m²-2ml=0
- 2lm=0
- Im = 0
- 1=0 or m=0
- If I = 0, we have m+n=0 and m²-n²=0
- 1=0, m=λ, n=-λ
- If m=0, we have 1+m=0 and 2-m²=0
- 1=-2, m=0, n=2
- So, the vector parallel to these given lines
- are a =j-k and b=-i+k.
- If angle between the lines is '6', then
- cos 8=
- cos 8= 2
- 8=
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