find the direction cosins of the straight line x = 2y = 5 y
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Answer:
take a point P on the straight line L x = 2 y = 5 z.
Take x = 10 (lcm of 2 and 5) y = 5 and z = 2. P = (10, 5 , 2)
this straight line L goes through the origin O.
the distance OP = r = √(10²+5²+2²) = √129
Direction cosines are (cos α, cos β, cos γ) = ( x/r , y/r, z/r )
= ( 10/√129, 5/√129, 2/√129)
Step-by-step explanation:
thank you
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