find the direction ratios of the vector perpendicular to the two lines whose direction ratios are a= i^+3j^+2k and b=i^+j^+2k
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Answer:
for dot product
a.b
a=i^+3j^+2k^
b=i^+j^+2k^
so, then
a.b= ( i^+3j^+2k^).(i^+j^+2k^)
(i. i=1,j. j=1,k. k=1 in dot product)
you will get
a.b =1+3+4
a.b = 8
this is the answer for dot product
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