Math, asked by nagusyyad18, 4 months ago

find the directional derivative of the Scalar point function pi=x^2y+y^2z+z^2x at the point (2,2,2) in the direction of thre normal to the surface 4x^2y+2z^2=2 at the point (2,-1,3)

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Answered by kirankumar02170

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Answered by friendshipvideos82

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find the directional derivative of the Scalar point function pi=x^2y+y^2z+z^2x at the point (2,2,2) in the direction of thre normal to the surface 4x^2y+2z^2=2 at the point (2

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find the directional derivative of the Scalar point function pi=x^2y+y^2z+z^2x at the point (2,2,2) in the direction of thre normal to the surface 4x^2y+2z^2=2 at the point (2,-1,3)​

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find the directional derivative of the Scalar point function pi=x^2y+y^2z+z^2x at the point (2,2,2) in the direction of thre normal to the surface 4x^2y+2z^2=2 at the point (2,-1,3)