Question

Find the discremenant of!
(2x+3) (3x-2) +2=0​

Answer 1

Answer:

Step-by-Step Explanation:

$(2x + 3)(3x - 2) + 2 = 0 \\ (6 {x}^{2} - 4x + 9x - 6) + 2 = 0 \\ (6 {x}^{2} + 5x - 6) + 2 = 0 \\ 6 {x}^{2} + 5x - 6 + 2 = 0 \\ 6 {x}^{2} + 5x - 4 = 0 \\ 6 {x}^{2} - 3x + 8x - 4 = 0 \\ 3x(2x - 1) + 4(2x - 1) = 0 \\ (2x - 1)(3x + 4) = 0 \\ 2x - 1 = 0 \: \: \: or \: \: \: 3x + 4 = 0 \\ 2x = 1 \: \: \: or \: \: \: 3x = - 4 \\ \boxed{ \large x = \underline{ \underline{ \frac{1}{2}}} \: \: \: or \: \: \: x = \underline{ \underline{ \frac{ - 4}{3} }}}$