Math, asked by LonePear, 8 months ago

find the discrimant of 3x²-2x+1/3=0 and the nature of the roots and find if it's real..​

Answers

Answered by bhattjyoti316
0

Answer:

3x²-2x+1=3

Step-by-step explanation:

3x²-2x+1=3

3x²-2x+1=3

3x²-2x+1=3

3x²-2x+1=3

3x²-2x+1=3

3x²-2x+1=3

Answered by jtg07
3

\green{question::}

{bold{underline{find\: discriminant}}}

discriminant \: is \:  {b}^{2}  - 4ac \\ in \: the \: given \: polynomial \:  \\ a = 3 \\ b = ( - 2) \\ c =  \frac{1}{3}  \\ thus \: discriminant \: is \:

 {( - 2)}^{2}  - 4(3)( \frac{1}{3} ) \\ 4 - 4(1) \\ 0

\yellow{when\:discriminant\:is\:equal\:to\0\:roots\:are\:equal\:and\:real\:

thus \: roots \: are \: real \: and \: equal

\red{thank\:you}

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