Question

find the discrimant of the
$\sqrt{5} x {}^{2} - 7x + 2 \sqrt{5}$​

Answer 1

Answer:

$\red {Discreminant (D)}\green {= 9}$

Step-by-step explanation:

$Compare \: \sqrt{5} x {}^{2} - 7x + 2 \sqrt{5}\:with\\ax^{2}+bx+c \: we \:get$

$a = \sqrt{5} , \:b = -7 \: c = 2\sqrt{5}$

$Discreminant (D) = b^{2} - 4ac \\= (-7)^{2} - 4\times \sqrt{5} \times 2\sqrt{5}\\= 49 - 40\\= 9$

Therefore.,

$\red {Discreminant (D)}\green {= 9}$

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