Question

find the discriment of 2x^2+x-4=0​

Answer 1

Step-by-step explanation:

$\huge\underline{\underline{\sf ANSWER}} \\ 2 {x}^{2} + x - 4 = 0 \\ a = 2 \\ b = 1 \\ c = - 4 \\ \\ x = \frac{ - b \: + \: / \: - \sqrt{ {b}^{2} - 4ac } }{2a} \\ x = \frac{ - 1 + \: / \: - \sqrt{1 + 8(4)} }{4} \\ x = \frac{ - 1 \: + / \: - \sqrt{33} }{4}$