Math, asked by vanajakuncham2, 1 year ago

Find the discriminan(X+5)^2=2(5x-3)

Answers

Answered by Anonymous
7

\underline {\Huge \mathfrak {Answer ;}}

(X+5)^2 = 2 ( 5x - 3)

=> x^2 + 2 × x ×5 + 25 = 10 x - 6

=> x^2 + 10x + 25 = 10x - 6

=> x^2 + 25 + 6 = 0

=> x^2 + 31 = 0

Hence, discriminant

= b^2 - 4ac

Here, b = 0, a = 1 , c = 31

So, discriminant = 0 - 4 × 1 × 31 = 0 - 124 = - 124


sabrinanandini2: This came in board exam!!
Answered by Anonymous
8

\huge\bf\pink{\mid{\overline{\underline{Your\: Answer}}}\mid}

-124

step-by-step explanation:

Given,

{(x+5)}^{2}= 2 ( 5x - 3)

on expansion,

we get,

=> {x}^{2} + 2 × (x )×(5) + 25 = 10x - 6

=> {x}^{2} + 10x + 25 = 10x - 6

on simplification,

we get,

=> {x}^{2}+ 25 + 6 = 0

=> {x}^{2} + 31 = 0

this is the required quadratic equation

here,

a = 1

b = 0

c = 31

Now,

we know that,

discriminant (D) ={b}^{2} - 4ac

putting rhe value of

b = 0, a = 1 , c = 31

in the equation,

we get,

D = 0 - 4 × 1 × 31

=> D = 0 - 124

=> D = - 124

hence,

descriminant = -124

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