Question

find the discriminant 3x^2-2x+8=0​

Answer 1

Given ,

The polynomial is 3x² - 2x + 8

We know that , the discriminant of quadratic equation is given by

$\large \sf \fbox{D = {(b)}^{2} - 4ac}$

Thus ,

$\Rightarrow \sf</p><p>D = {( - 2)}^{2} - 4 × 3 × 8 \\ \\ \Rightarrow \sf</p><p>D = 4 - 96 \\ \\ \Rightarrow \sf</p><p>D = - 92 < 0$

$</p><p> \therefore \sf \bold{ \underline{The \: quadratic \: eq \: has \: unequal \: and \: imaginary \: roots}}$

Answer 2

Answer:

Given,

The polynomial is 3x-2x +8

We know that, the discriminant of

quadratic equation is given by

Marge Isf fbox[D = {(b)2) - 4ac)

/p>< p> D = (-2)-4 x 3 x8

Thus