Question

find the discriminant 5rootx^2 + 8x - 3root2 = 0​

Answer 1

Correct question :-

Find discriminant of √5x²+8x-3√2=0

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Solution :-

To find the discriminant, we have following formula:

$\large\underline{\boxed{\star\;\;\sf D=b^2-4ac}}$

$\pmb{\sf Here}\begin{cases}\sf D\:is\: discriminant\\\sf b\:is\: coefficient\:of \:x\\\sf a\:is\: coefficient\:of\:x^2\\\sf c\:is\: constant\:term\end{cases}$

So, value of:

• a is √5

• b is 8

• c is -3√2

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We have to find value of D. So let's apply above formula!

$\pmb{\sf \implies D=b^2-4ac}$

$\sf \implies D=(8)^2-4(\sqrt{5})(-3\sqrt{2})$

$\sf \implies D=64+12(\sqrt{10})$

$\sf \implies D=4(16+3\sqrt{10})$

$\sf \implies D=4[16+3(3.16)]$

$\sf \implies D=4[16+9.48]$

$\sf \implies D=4(25.48)$

$\pmb{\boxed{\sf \implies D=101.94}}$

This is the required value of discriminant.

Also note that value of discriminant is possible even in decimal or square root.

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