Question

find the discriminant and if the real root exist then also find root 2x²-12x+18=0​

Answer 1

Answer:

Step-by-step explanation:

Let p ( 2) = 2x² - 12x + 18 = 0 ⇒ x² - 6x + 9 = 0

Comparing the given equation with ax² +bx + c = 0,

We have a = 1 , b = - 6 and c = 9.

∴Discriminant = d = b² - 4ac = ( - 6 )² - 4 ( 1 ) ( 9 ) = 36 - 36 = 0.

∴x = - b ± √b² - 4ac / 2a

= - ( - 6 ) ± √ 0 / 2 ( 1 ) (∵ b² - 4ac = 0 )

= 6 ± 0/2

= 6 ± 0

= 6 is the answer.