Find the discriminant for the following quadratic equations. Also, determine the nature of the roots. X^2 - 3 root 3x + 12 = 0
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To find :
The discriminant for the following quadratic equations. Also, determine the nature of the roots. X^2 - 3 root 3x + 12 = 0.
Answer:
Discriminant of ax^2 + bx + c = 0 is given by b^2 - 4ac.
Here,
a = 1, b = - 3√3, c = 12
So Discriminant is
→ ( - 3√3 )^2 - 4( 1 * 12 )
→ 27 - 48
→ - 21
As Discriminant is -ve, value under the square root will be negative and square on any negative number doesn't exists.
Hence roots are unequal and non-real
Answered by
0
Answer:
x2+6x+9=0
Step-by-step explanation:
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