Math, asked by himanshusinghbbps, 10 months ago

Find the discriminant for the following quadratic equations. Also, determine the nature of the roots. X^2 - 3 root 3x + 12 = 0

Answers

Answered by stylishtamilachee
32

To find :

The discriminant for the following quadratic equations. Also, determine the nature of the roots. X^2 - 3 root 3x + 12 = 0.

Answer:

Discriminant of ax^2 + bx + c = 0 is given by b^2 - 4ac.

Here,

a = 1, b = - 3√3, c = 12

So Discriminant is

→ ( - 3√3 )^2 - 4( 1 * 12 )

→ 27 - 48

→ - 21

As Discriminant is -ve, value under the square root will be negative and square on any negative number doesn't exists.

Hence roots are unequal and non-real

Answered by Alexjayascan3
0

Answer:

x2+6x+9=0

Step-by-step explanation:

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