Question

Find the discriminant for the quadratic equation 2(p 2 + q 2 )x 2 + 2(p + q)x + 1 = 0 (p ≠ q). Also, determine the nature of the roots.

Answer 1

Answer:

Step-by-step explanation: 2(p² + q² )x² + 2(p + q)x + 1 = 0  

from the equation above a=2(p²+q²), b=2(p+q),=1

discriminant=delta=Δ=b²-4ac

⇒Δ=[2(p+q)]²-4[2(p²+q²)][1]

     =(2²×(p+q)²)-8(p²+q²)

     =(4×(p²+q²+2pq) )-8(p²+q²)

     =(4p²+4q²+8pq)-8(p²+q²)

     =8pq+4(p²+q²)-8(p²+q²)

     = 8pq-4(p²+q²)

Answer 2

Answer:

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Step-by-step explanation:

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