Question

find the discriminant of 2 X square + 10 X + 21 is equal to zero​

Answer 1

Answer:

D=b^2-4*ac

=(10)^2-4*2*21

=100-168

= -68

Answer 2

Answer:

-68

Step-by-step explanation:

• 2x^2 +10x + 21=0
• √D (discriminant) = b^2 - 4ac
• here comparing above equation with ax^2 + bx + c = 0

we get a= 2, b= 10, c= 21

• √D = 10^2 - 4 x 2 x 21
• √D = 100 - 168
• √D = -68

Since discriminant is less than 0 therefore it will have imaginary roots

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