Question

Find the discriminant of 36x2-12ax+(a2-b2)=0
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Answer 1

Answer:

36x2 -12ax+(a2-b2)

Step-by-step explanation:

• = (6x2)-2×6a+ (a2-b2)=0 =(6x-a2)-(b2)=0=(6x-a+b)(6x-a -b)=0 =6x-a+b=0 =x=a-b÷2 =6x-a-b=0 =1÷(x+4)-1 (x-7)=11÷30 multiple both side by 30 (x+4)(x-7) 30 (x-7)-30 (x+40) =11 (x+4) (x-7)=30x-210-30x-120= 11(x2-3x-28) =-330= 11 (x2-3x -28)=x2 -3x+2=0 =(x-1) (x-2)=0 =x=1=x=2