Find the discriminant of an equation x square minus 3 root 5 x minus 2 root 3 is equals to zero check whether the roots are real and if real find the roots?
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Answer:
discriminant of an equation = b^2-4ac
here a= 1, b= -3√5 ,c= -2√3
b^2-4ac = (-3√5)^2 - 4*1*(-2√3)
=45+8√3
= positive
therefore, the roots are real and unequal
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