Question

find the discriminant of bx2-2√ac x+b=0.

Answer 1

$d = b {}^{2} - 4ac$
d=(-2√ac)^2-4b*b
d=4ac-4b^2

Answer 2

Answer:

d=b

2

−4ac

d=(-2√ac)^2-4b*b

d=4ac-4b^2