Question

Find the discriminant of equation 5 x square - 4 root 5 x + 4=0 and hence find the nature of roots

Answer 1

✌Hello..✌.. Your answer is ⤵⤵⤵
$5{x}^{2} - 4 \sqrt{5x} + 4 = 0$

$for \: discriminant \: =>>$

$formula = \frac{ - b ± \sqrt{b}^{2} - 4ac }{2a}$

$a = 5$

$b = - 4 \sqrt{5}$

$c = 4$

$\sqrt{b {}^{2} - 4ac} = \sqrt{ { - 4 \sqrt{5} }^{2} - 4(5)(4)}$

$\sqrt{16 \times 5 - 20 \times 4} = \sqrt{80 - 80}$

$\sqrt{0} = 0$

${b}^{2} - 4ac = 0$

$roots \: are \: equal \: and \: real..$