Question

find the discriminant of ethe equation 2x^2-4x+1/2=0​

Answer 1

Answer:

$given \: 2 {x}^{2} - 4x + \frac{1}{2} \\ \\ here \: a = 2 \\ \\ b = - 4 \\ \\ c = \frac{1}{2} \\ \\ and \: we \: know \: discriminant \: formula \: is \\ \\ {b}^{2} - 4ac \\ \\ = {( - 4)}^{2} - 4 \times 2 \times \frac{1}{2} \\ \\ = 16 - 4 \times 2 \times \frac{1}{2} \\ \\ = 16 - \frac{8}{2} \\ \\ = 16 - 4 \\ \\ = 12$

hope this much helps uh ❣️

Answer 2

Answer:

D = b² - 4ac

D = (-4)² - [ 4×2×1/2]

D = 16 - 4

D = 12

as D > 0, the equation has real distinct roots