Find the discriminant of quadratic equation x square - 4 x + 1 is equal to zero
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Answered by
13
Answer:
Discriminant of the given equation is 12.
Step-by-step explanation:
x^2 - 4x + 1 = 0.
Coefficient of x^2 be a, coefficient of x be b, and constant no be c.
Then,
a = 1
b = - 4
c = 1
Discriminant D = b^2 - 4ac
D = (-4)^2 - 4 ☓ 1 ☓ 1.
D = 16 - 4
D = 12. ✔️✔️
➡️ Root 1st = b+ sqrt D /2a
Root 1 = - 4 + 2root 3/2
Root 1 = root3 - 2
➡️ Root 2nd = b - sqrt D/2a
➡️ Root 2nd = - 4 - 2 root3/2
➡️ Root 2nd = - (2 + root3)
Krais:
Root 3 means 3 under root or sqrt of 3 which is equal to 1.732 approx.
Root 1 and root 2nd are the values of x which will satisfy the equation or they are the roots of eqn
Answered by
12
HERE'S THE ANSWER,
therefore,
a = 1, b = -4, c = 1
= b^ - 4ac
= (-4)^ - 4×1×1
= 16 - 4
= 12 > 0
therefore, roots are real and distinct.
HOPE IT HELPS
PLEASE MARK AS BRILLIANIST
:-))
therefore,
a = 1, b = -4, c = 1
= b^ - 4ac
= (-4)^ - 4×1×1
= 16 - 4
= 12 > 0
therefore, roots are real and distinct.
HOPE IT HELPS
PLEASE MARK AS BRILLIANIST
:-))
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