Math, asked by Arulkumaran6622, 10 months ago

Find the discriminant of quadratic equation x square - 4 x + 1 is equal to zero

Answers

Answered by Krais
13

Answer:

Discriminant of the given equation is 12.


Step-by-step explanation:

x^2 - 4x + 1 = 0.

Coefficient of x^2 be a, coefficient of x be b, and constant no be c.

Then,

a = 1

b = - 4

c = 1

Discriminant D = b^2 - 4ac

D = (-4)^2 - 4 ☓ 1 ☓ 1.

D = 16 - 4

D = 12. ✔️✔️

➡️ Root 1st = b+ sqrt D /2a

Root 1 = - 4 + 2root 3/2

Root 1 = root3 - 2

➡️ Root 2nd = b - sqrt D/2a

➡️ Root 2nd = - 4 - 2 root3/2

➡️ Root 2nd = - (2 + root3)


Krais: Root 3 means 3 under root or sqrt of 3 which is equal to 1.732 approx.
Krais: Root 1 and root 2nd are the values of x which will satisfy the equation or they are the roots of eqn
Answered by erfankhan
12
HERE'S THE ANSWER,

therefore,
a = 1, b = -4, c = 1
= b^ - 4ac
= (-4)^ - 4×1×1
= 16 - 4
= 12 > 0
therefore, roots are real and distinct.

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