Question

Find the discriminant of the equation 2x² - 6x+3=0 and hence find the
nature of its roots. If the real root exists, find them.​

Answer 1

∆= b²-4ac

=(-6)²-4×2×3

=36-24

=12

The roots are real

Answer 2

Answer:

a=2 , b=-6 ,c=3

Step-by-step explanation:

b^2- 4ac

(-6),^2-4×2×3

36-24

12 (real and different root)

2x^2-6x+3=0

x = -b +-√b^2-4ac/2a

x = -6 +-√(-6)^2-4×2×3/2×2

x = -6 +-√ 36-24/4

x = -6 +-√12/4

x = -6 +- 3

(+)

-6+3

-3

(-)

-6-3

-9