Question

find the discriminant of the equation 3 x square - 2 X + 1 by 3 is equal to zero ​

Answer 1

${ \huge \bf{ \mid { \overline{ \underline{AnSwEr}}} \mid}}$

$\large\therefore\sf\green{d = +2\sqrt{2}, -2\sqrt{2} }$

$\large{\sf{\underline{\underline{ExpLanaTiOn:-}}}}$

Given:-

$\large\rm\ 3x^2 -2x +1$

Here,

•a = 3

•b = 2

•c = 1

To find :-

Discriminant of given quadratic equation

Solution:-

$\large\purple{\boxed{\rm d = \sqrt{b^{2} - 4ac} }}$

Now,

$\large\implies\sf\ d = \sqrt{(2)^2- 4 \times 3 \times 1} \\ \\ \large\implies\sf\ d = \sqrt{4 - 12} \\ \\ \large\implies\sf\ d= \sqrt{-8} \\ \\ \large\implies\sf\ d = +2\sqrt{2}, -2\sqrt{2}$

Answer 2

Answer:

Given eq :

$({3x}^{2} - 2x + 1) \div 3$

x^2-(2/3)x+1/3

a=1, b=-2/3, c=1/3

discriminant = (b^2-4ac)^1/2

Let discriminant be denoted by d.

d^2 = (2/3)^2-4(1)(1/3)

= 4/9-4/3

d^2 = - 8/9

d = (2(-2)^1/2)/3

Discriminant =

$discrimnant \: = 2 \sqrt{ - 2} \div 3$