Find the discriminant of the equation 3x^2 -2x+1/3 = 0 and hence find the nature of its roots. Find them, if they are real
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3x² -6x -4 = 0
0 =b² -4ac
0 =(-6)² -4 × 3 ×(-4)
0 =36 - 48
Now, x = (-b ± √-12) ÷2 ×3
x = (-6 ± √-12) ÷ 6
Because√-12 is an imaginary number,
Therefore, It has no real roots nature of the roots - unreal.
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