Question

find the discriminant of the equation 3x²-2x+1 =0 and hence find the nature of roots.​

Answer 1

Answer:

<p>3x² + 2x - 1 = 0<br>Here a = 3, b = 2, c = -1<br>∴ D = b² - 4ac<br>= (2)² - 4 x 3 x (-1)<br>= 4 + 12<br>= 16<br>∴ Discriminant = 16<br>∵ D &gt; 0<br>∴ Roots are real and distinct.</p>

Step-by-step explanation:

Answer 2

Answer:

discriminant=b^2-4ac

in the above equation let a=3 b= -2 and c=1

now substituting the values

(-2)^2-4.1.3

4-12= -8

we know that if discriminant is equal to zero then we get one real root

if It's greater than zero then we get two real roots

if less than zero...the roots are imaginary..

hence the above roots are imaginary

hope this helps