Question

find the discriminant of the equation 3xsq - 2x +1/3 =0 and hence the nature of the roots​

Answer 1

Step-by-step explanation:

3x²-2x+⅓=0

we already know that, ax²+bx+c=0 is the common structure of quadratic equations with one variable.

so, there is , a=3 , b= -2 and c=⅓

so, discriminant= b²-4ac

=(-2)²-4×3×⅓

=4-4=0

so, two roots are real and equal. ( it's the the nature of the both roots)

3x²-2x+⅓=0

or, 3x²-x(1+1)+⅓=0

or, 3x²-x-x+⅓=0

or, 3x(x-⅓)-1(x-⅓)=0

or, (x-⅓)(3x-1) =0

So, x-⅓=0 , then, 3x-1=0

or, x=⅓ or, 3x=1

or, x=⅓

So, x = ⅓ or ⅓