Question

Find the discriminant of the following equation √3x^2+2√2x-2√3=0
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Answer 1

$√3x^2+2√2x-2√3=0$

Disseminate ( 0 ) = B² - 4A C

∆ >0 Roots⏩ Real L unequal

∆ = 0 Roots⏩ Real L Equal

∆ < 0 Roots ⏩ Imaginary

$\sqrt{3x {}^{2} } = 5 = x - 2 \sqrt{3} = 0$

$a = \sqrt{ 3} \: \: b = 5 = c = - 2 \sqrt{3}$

∆ = B² - 4ac

= ( 52 ) - 4 ( 53 ) ( -253 )

= 2 ( -8 ) ( 53 )²

= 2 + 8 × 3

= 2 + 24 = 26

26>0

= ∆>0 = Roots are real S unequal.

$\huge \boxed{Roots \: are \: real \: S \: unequal.} \\ is \: your \: answer$

Answer 2

Answer:

Heya !!

The given equation is √3X² - 2√2X - 2√3 = 0

Here,

a = √3 , b = -2√2 and c = -2√3.

Discriminant ( D ) = B²-4AC

=> (-2√2)² - 4 × √3 × -2√3

=> 8 + 24

=> 32

✓D = √32 = √2 × 2 × 2 × 2 × 2 = 4√2.

Roots of the given equation are : -B + √D/2A and -B - √D/2A

=> - (-2✓2) + 4√2 / 2√3 and -(-2√2) - 4√2/2√3

=> ( 2√2 + 4√2 ) /2√3 and (2√2 - 4√2 ) /2√3

=> ( 6√2/2√3 ) And ( -2√2/2√3 ).

=> ( 3√2/√3 ) and ( -√2/√3)

=> ( √3 × √3 × √2/✓3) and ( -√2/√3)

=> ( √3 × √2 ) and ( -√2/✓3)

=> ( √6 ) and ( -√2/√3).