Question

find the discriminant of the following quadratic equation under root 3 X 2 - 2 under root 2 x minus 2 under root 3 is equal to zero​

Answer 1

Answer:

the roots are real

Step-by-step explanation:

$3 {x}^{2} - 2 \sqrt{2} x - 2 \sqrt{3} = 0 \\ a = 3 \: \: b = - 2 \sqrt{2} \: \: c = - 2 \sqrt{3} \\ discriminant = {b}^{2} - 4ac \\ {( - 2 \sqrt{2} )}^{2} - 4(3)( - 2 \sqrt{3} ) \\ 8 + 24 \sqrt{3} > 0$

the t

Answer 2

Step-by-step explanation:

Compare given equation with the general form of quadratic equation, which is ax

2

+bx+c=0

Here, a=

3

,b=2

2

,c=−2

3

Discriminant formula: D=b

2

−4ac

=(2

2

)

2

−4(

3

)(−2

3

)

D=32