Question

Find the discriminant of the quadratic equation 2x2 - 4x+ 3=0 and
hence find the nature of its roots.​

Answer 1

Answer:

2x^2 - 4x+3=0,, here a=2, b=-4,c=3

Descriminant=b^2 - 4ac

(-4)^2 - 4(2)(3)

16-24

-8

Roots are not real

Answer 2

$2 {x}^{2} - 4x + 3 = 0$

$let \: \: a = 2 \: \: b = - 4 \: \: \: c = 3$

NOW,

D

$D = {b }^{2} - 4ac$

$D = ( - 4)^{2} - 4 \times 2 \times 3$

$D = 16 - 24$

$D = - 8$

therefore, root of quadratic equation are not real.

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