Question

Find the discriminant of the quadratic equation 2x2 – 4x + 3 and find the nature of its roots.​

Answer 1

2x² - 4x + 3

Here

a = 2

b = -4

c = 3

Discriminant = b² - 4ac

⇒ Discriminant = (-4)² - 4×2×3

⇒ Discriminant = 16 - 24

Therefore Discriminant = -6

Since discriminant is less than 0, the quadratic equation has no real roots.

Additional information:

• If Discriminant is greater than 0, the equation has 2 distinct real roots.
• If Discriminant is lesser than 0, then the equation has 2 equal real roots.

Answer 2

To find out the discriminant of the

quadratic equation: 2x^2-4x+3

D=b^2-4ac

D=4^2-4*2*3

D=16-24= -8

because the discriminant is -8 and as we know that it's

a negative digit

so therefore, the roots are not real and does not exist