Find the discriminant of the quadratic equation 2x2 - 6x + 3 = 0 then find the nature of
roots
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Step-by-step explanation:
in quadratic equation 2X2 -6x +3 =0
here, a =2 ,b = -6 and c=3
to find the nature of root
D = b2 - 4ac
D = (-6)2 - 4*2*3
D = 36 -24
D = 12
if b2 -4ac >0
so it is two distinct real root
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