Find the discriminant of the quadratic equation 2x2– 6x + 3 = 0, and hence find the nature of its roots
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2x²-6x+3=0 ( a= 2 b= -6 c= 3)
discriminant (d) = b²-4ac
= (-6)² - 4 ×2×3
= 36-24
= 12
Ans : here discriminant >0 so roots are real
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