Question

Find the discriminant of the quadratic equation 2x2-6x+3=0 and hence write the
nature of roots.​

Answer 1

Answer:

Step-by-step explanation:

The equation is 2x² - 6x + 3 = 0

Discriminant = b² - 4ac

Here a = 2,   b = -6    , c = 3

Therefore discriminant is equal to

⇒(-6)² -4 × 2 ×3

⇒36 - 24

⇒12

12 > 0

Therefore since b² - 4ac is greater than zero

∴Zeroes are real and distinct

More info:

• If Discriminant is lesser than zero ,there are no real roots for the equation
• If discriminant is equal to zero then the roots are real and equal.

Answer 2

$2 {x}^{2} - 6x + 3 = 0 \: \\ (a = 2 \: \: b = - 6 \: \: c = 3) \\ \: discriminate \:( d) = {b}^{2} - 4ac \\ = ( - 6 {)}^{2} - 4 \times 2 \times 3 \\ = 36 - 24 \\ = 12 \\ here \: discriminate \: \\ > 0 \: so \: roots \: are \: real$