Question

find the discriminant of the quadratic equation 3x^2-6x-4=0 and hence find nature of roots​

Answer 1

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Answer 2

3x² -6x -4 = 0

0 =b² -4ac

0 =(-6)² -4 × 3 ×(-4)

0 =36 - 48

Now, x = (-b ± √-12) ÷2 ×3

x = (-6 ± √-12) ÷ 6

Because√-12 is an imaginary number,

Therefore, It has no real roots nature of the roots - unreal.

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