find the discriminant of the quadratic equation 3x² – 5x + 7 = 0 and hence find the nature of its roots.
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You have 3x^2 + 5x + 7 = 0.
x1 = [-5+(5^2–4*3*7)^0.5]/6
= [-5+(25–84)^0.5]/6
= [-5+(-59)^0.5]/6
x2 = [-5-(5^2–4*3*7)^0.5]/6
= [-5-(25–84)^0.5]/6
= [-5-(-59)^0.5]/6.
So x has two imaginary values: x1 = [-5+(-59)^0.5]/6 and
x2 =[-5-(-59)^0.5]/6
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