Question

find the discriminant of the quadratic equation
$2 {x }^{2} - 4x + 3 = 0$

Answer 1

a = 2 , b = -4 , c = 3

discrimant = b²-4ac
= (-4)² - 4(2)(3)
= 16 - 24
= -8

b²-4ac < 0

the roots are not real

Answer 2

Heya !!!

This is your answer.....

Given equation ::: ----
2x^2 - 4x + 3 = 0.

By comparing this equation with ax^2+bx+c =0.
We get
a = 2.
b = -4
c = 3.

Discrimanant = b^2 - 4 × a × c
= (-4)^2 - 4 × 2 × 3
= 16 - 24
= -8.

Hence, the disciminant of given equation is -8.

Hope it helps