Question

find the discriminant of the quadratic equation x2-1=0 and also find the roots of the equation

Answer 1

The equation is $x^{2} -1$=0
Here, a=1
          b=0
          c=-1

Discriminant=D=$b^{2}$-4ac
                        =$0^{2}$-4(1)(-1)
                         =4
Roots of the equation are
x=-b+/-$\sqrt{D}$/2a
 

x=-b+$\sqrt{D}$/2a  or x=-b-$\sqrt{D}$


x=-b+$\sqrt{D}$/2a
  =-(0)+$\sqrt{4}$/2(1)
   =2/2=1

x=-b-$\sqrt{D}$/2(1)
  =-2/2=-1


therefore the roots of the equation are 1,-1
  =

Answer 2

Answer:

The equation is x2 - 1 =0

Here, a=1

b=0

C=-1

Discriminant=D=62-4ac

=02 -4(1)(-1)

=4

Roots of the equation are x=-b+/- D 72a

x=-b+VD /2a or x=-b-VD

xe-b+VD /2a

=-(0)+v4 /2(1)

=2/2=1

x=-b-V D /2(1) =-2/2=-1

therefore the roots of the equation are 1,-1